Ruby regex syntax for "not matching one of the following" -

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nice simple regex syntax question you.

i have block of text , want find instances of href=" or href=' not followed either [ or http://

i can "not followed [" with

record.body =~ /href=['"](?!\[)/

and can "not followed http://"

record.body =~ /href=['"](?!http\:\/\/)/

but can't quite work out how combine two.

just clear: want find bad strings this

`href="www.foo.com"`

but i'm ok (ie don't want find) strings this

`href="http://www.foo.com"` `href="[registration_url]"`

combine both using alternation operator.

href=['"](?!http\:\/\/|\[)

for more specific, be.

href=(['"])(?!http\:\/\/|\[)(?:(?!\1).)*\1

this handle both single quoted or double quoted string in href part. , won't match strings href='foo.com" or href="foo.com' (unmatched quotes)

(['"]) capture double quote or single quote. (?!http\:\/\/|\[) , matched quote won't followed http:// or [, if yes, moves on next pattern. (?:(?!\1).)* matches character not of captured character, 0 or more times. \1 followed captured character.

demo


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