for loop - awk increment the input field while looping -

i have loop on array. looking on $11 field. however, want check different field every time.

• when i first element, want @ $11 field.
• when i second element, want @ $12 field.
• when i third, want @ $13 field.

i using:

for in "${array[@]}"     awk -v ofs="\t" -v str1="$i" -v thr="$thr" '{ if($11>=thr)  print "chr" $1, $2 ,$3 , str1 ;}' comb.txt > $i".bed"     done 

how can this?

my variables follows:

str1="cd45ra+_naive" str2="cd45ro+_mem" str3="cd127-_treg" str4="il17-_th_stim_macs" str5="il17+_th17_stim" array=($str1 $str2 $str3 $str4 $str5) thr=10 

given array names, can loop through values , know index doing:

for ((i=0; i<${#names[@]}; i++))    echo "$i, ${names[$i]}" done 

for example,

$ names=('a' 'b' 'c') $ ((i=0; i<${#names[@]}; i++)); echo "$i, ${names[$i]}"; done 0, 1, b 2, c 

based on logic, in case can say:

for ((i=0; i<${#array[@]}; i++))    awk -v index="$i" -v str1="${names[$i]}" -v thr=$thr '{ if($(index+11)=>thr) ... }' comb.txt        ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^                 ^^^^^^^^^^^^^^ done 

that is, providing index $i index awk , value ${names[$i]} str. then, within awk code can play around index value, saying index + 10 or whatever need number.